Here is a simple Java program for beginners,
Write a Java program to find a leap year or not.
Formula for finding a Leap year is as follows:
1. A year should be evenly divisible by 4 (should not have a reminder):
year % 4 == 0 ( reminder should be 0 )
2. AND Year should not be evenly divisible by 100 (should have a reminder):
year % 100 != 0 ( reminder should not be 0 )
3. OR Year should be evenly divisible by 400 (should have a reminder):
year%400 == 0 ( reminder should be 0 )
So basically 1 && 2 || 3
if (1 and 2) both are true or 3 is true then it is a leap year
Here is the Java program to find the leap year,
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import java.util.Scanner; /** * * @author agur */ public class LeapYear { public static void main(String[] args) { int year; Scanner in = new Scanner(System.in); System.out.println("Enter a year:"); year = in.nextInt(); if ((0 == year % 4) && (0 != year % 100) || (0 == year % 400)) { System.out.println(year+" is a leap year"); } else { System.out.println(year+" is not a leap year"); } } } |
The output of the above program will be:
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run: Enter a year: 1997 1997 is not a leap year BUILD SUCCESSFUL (total time: 3 seconds) |
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run: Enter a year: 1996 1996 is a leap year BUILD SUCCESSFUL (total time: 1 second) |
Hope this post will be helpful for Java Beginners.
