In this post, we are going to see how to write a C program to find Student Total marks & Percentages.
What will you learn in this C program?:
- How to get the number of subjects dynamically.
- You will learn how to set a dynamic array variable in C.
- Get the size of an array in C.
- How to find the percentage in C language.
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#include <stdio.h> int main() { //set the integers int subj, i, mark; float total = 0, percentage; printf("No. of Subjects?: "); scanf("%d", &subj); //dynamic array int marks[subj]; //get the array size int arr_size = sizeof(marks) / sizeof(marks[0]); //for loop to get the marks & calculate them for(i=0; i < arr_size; i++) { printf("Subject %d:", i+1); scanf("%d", &mark); total = total + mark; } //let's find the percentage percentage = ( total / arr_size * 100) / 100; //print the result printf("Total marks = %f\n", total); printf("Percentage = %f\n", percentage); return 0; } |
Output:
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No. of Subjects?: 6 Subject 1:98 Subject 2:95 Subject 3:85 Subject 4:79 Subject 5:81 Subject 6:80 Total marks = 518.000000 Percentage = 86.333344 -------------------------------- Process exited after 23.24 seconds with return value 0 Press any key to continue . . . |
Read the inline comments to understand each section of the program. I believe this post would have helped you to understand how to write a C program to find Student marks.
